What does the following code output? console.log(‘a’); setTimeout(() => console.log(‘b’), 0); Promise.resolve().then(() => console.log(‘c’)); console.log(‘d’);

JavaScript Developer Medium

JavaScript Developer — Medium

What does the following code output? console.log(‘a’); setTimeout(() => console.log(‘b’), 0); Promise.resolve().then(() => console.log(‘c’)); console.log(‘d’);

Key points

The order of execution is determined by the event loop in JavaScript
setTimeout() with 0ms delay doesn't guarantee immediate execution
Promises are asynchronous and executed after the current call stack is empty

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