What does the following code output? def make_counter(): count = 0 def increment(n=1): nonlocal count count += n return count def reset(): nonlocal count count = 0 increment.reset = reset return increment c = make_counter() c(3) c(2) c.reset() print(c())

Python Professional Hard

Python Professional — Hard

What does the following code output? def make_counter(): count = 0 def increment(n=1): nonlocal count count += n return count def reset(): nonlocal count count = 0 increment.reset = reset return increment c = make_counter() c(3) c(2) c.reset() print(c())

Key points

The counter starts at 0 and is incremented by 3 and then 2.
The reset function sets the counter back to 0.
The final output is the result of the last increment operation.

Ready to go further?

Start full exam Practice more questions

Related questions