What is the result of the following code snippet? const obj = { x: 10 }; Object.defineProperty(obj, ‘x’, { writable: false, configurable: false }); Object.freeze(obj); obj.x = 20; console.log(obj.x);

Question

Select the correct answer: Single Choice

Accepted Answer

The property 'x' is already non-writable and non-configurable. Freezing the object makes all properties non-writable and non-configurable. In non-strict mode, assigning to a non-writable property fails silently, leaving the original value intact. In strict mode, it would throw a TypeError. Since no 'use strict' is present, the assignment fails silently and the value remains 10.