Which statement correctly describes the scope of variables defined within a closure using the ‘use’ keyword?

Question

PHP Intermediate — Hard

Which statement correctly describes the scope of variables defined within a closure using the ‘use’ keyword?

Accepted Answer

Variables inherited by a closure via the 'use' clause are passed by value by default. This means the closure receives a copy of the variable at the time the closure is created. To modify the original variable, one must explicitly use the reference operator (&) in the 'use' clause. They are not global, nor are they automatically passed by reference.