What is the output of the following? “`js const gen = function*() { const x = yield 1; const y = yield x + 2; return y; }; const g = gen(); console.log(g.next().value); console.log(g.next(10).value); console.log(g.next(20).value); “`

Question

JavaScript Professional — Medium

What is the output of the following? “`js const gen = function*() { const x = yield 1; const y = yield x + 2; return y; }; const g = gen(); console.log(g.next().value); console.log(g.next(10).value); console.log(g.next(20).value); “`

Accepted Answer

The output of the code is 1, 12, 20. The first `console.log(g.next().value)` returns 1 since no argument is passed to the `next()` method. The second `console.log(g.next(10).value)` returns 12 because 10 is passed as an argument to the `next()` method. The third `console.log(g.next(20).value)` returns 20 because 20 is passed as an argument to the `next()` method.